# Maths

# Introduction

To uses these functions and features, do not forget to put this line of code in your "using" region:

C#

using LeoCorpLibrary;

VB

Imports LeoCorpLibrary

# Maths Functions

There is multiple functions availables in this part of LeoCorpLibrary.

# a. Sum

This function is available in version 1.3 and higher

Compatibility
Framework LeoCorpLibrary LeoCorpLibrary.Core
.NET 5
.NET Core 3.1
.NET Framework 4.7.2
.NET Framework 4.5

The Sum() method enables you to do a sum of double numbers.

It's in:

LeoCorpLibrary.Maths.Sum()

You need to specify the numbers which you wanna get the sum of, in the argument section of the method.

Note

You can specify negative numbers.

Here's an example of usage:

C#

double numberSum = Maths.Sum(0, 2, 5, 6, 4);

VB

Dim numberSum As Double = Maths.Sum(0, 2, 5, 6, 4)

Go to top

# b. GetBiggestNumber

This function is available in version 1.3 and higher

Compatibility
Framework LeoCorpLibrary LeoCorpLibrary.Core
.NET 5
.NET Core 3.1
.NET Framework 4.7.2
.NET Framework 4.5

The GetBiggestNumber() allows you to get the biggest number among double numbers that are specified. Returns a doublevalue.

It's in:

LeoCorpLibrary.Maths.GetBiggestNumber()

Note

You can use negative numbers

Here's an example of usage:

C#

double biggestNumber = Maths.GetBiggestNumber(0, 2, 3, 4, 5, 9, 8, 1);

VB

Dim biggestNumber As Double = Maths.GetBiggestNumber(0, 2, 3, 4, 5, 9, 8, 1)

Go to top

# c. GetLowestNumber

This function is available in version 1.3.1 and higher

Compatibility
Framework LeoCorpLibrary LeoCorpLibrary.Core
.NET 5
.NET Core 3.1
.NET Framework 4.7.2
.NET Framework 4.5

The GetLowestNumber() method allows you to get the lowest number among double numbers that are specified. Returns a double value.

It's in:

LeoCorpLibrary.Maths.GetLowestNumber()

Note

You can use negative numbers.

Here's an example of usage:

C#

double lowestNumber = Maths.GetLowestNumber(0, 2, -1, 2.32);

VB

Dim lowestNumber As Double = Maths.GetLowestNumber(0, 2, -1, 2.32)

Go to top

# d. RadiansToDegrees

This function is available in version 3.5 and higher

Compatibility
Framework LeoCorpLibrary LeoCorpLibrary.Core
.NET 5
.NET Core 3.1
.NET Framework 4.7.2
.NET Framework 4.5

The RadiansToDegrees() method allows you to convert radians to degrees. Returns a double value.

It's in:

LeoCorpLibrary.Maths.RadiansToDegrees()

It has one argument:

Value Argument Description Example
double radians Radians to convert 1.5

Here's an example of usage:

C#

double degrees = Maths.RadiansToDegrees(1.57079633);
// Expected result: 90°

VB

Dim degrees As Double =  Maths.RadiansToDegrees(1.57079633)
' Expected result: 90°

Go to top

# e. DegreesToRadians

This function is available in version 3.5 and higher

Compatibility
Framework LeoCorpLibrary LeoCorpLibrary.Core
.NET 5
.NET Core 3.1
.NET Framework 4.7.2
.NET Framework 4.5

The DegreesToRadians() method allows you to convert degrees to radians. Returns a double value.

It's in:

LeoCorpLibrary.Maths.DegreesToRadians()

It has one argument:

Value Argument Description Example
double degrees Degrees to convert 60

Here's an example of usage:

C#

double degrees = Maths.DegreesToRadians(90);
// Expected result: 1.57079633

VB

Dim degrees As Double =  Maths.DegreesToRadians(90)
' Expected result: 1.57079633

Go to top

# e. IsInteger

This function is available in version 3.11 and higher.

Compatibility
Framework LeoCorpLibrary LeoCorpLibrary.Core
.NET 5
.NET Core 3.1
.NET Framework 4.7.2
.NET Framework 4.5

The IsInteger() method allows you to check if a double number is an integer (int) or not.

It's in:

LeoCorpLibrary.Maths.IsInteger()

This method has one argument:

Type Argument Description
double number The number to test

Here's an example of usage:

C#

bool isInt = Maths.IsInteger(10.5);
// isInt = false

bool isInt2 = Maths.IsInteger(4);
// IsInt2 = true

VB

Dim isInt As Boolean = Maths.IsInteger(10.5);
' isInt = false

Dim isInt2 As Boolean = Maths.IsInteger(4);
' IsInt2 = true

Go to top

# Circle

# a. GetArea

This function is available in version 1.3 and higher

Compatibility
Framework LeoCorpLibrary LeoCorpLibrary.Core
.NET 5
.NET Core 3.1
.NET Framework 4.7.2
.NET Framework 4.5

The GetArea() method allows you to get the area of circle. Returns a double value.

It's in:

LeoCorpLibrary.Maths.Circle.GetArea()

This method has one argument:

Value Argument Description Example
double radius Circle's radius 15.12

Here's an example of usage:

C#

double circleArea = Maths.Circle.GetCircleArea(12.458);

VB

Dim circleArea As Double = Maths.Circle.GetCircleArea(12.458)

Go to top

# b. GetPerimeter

This function is available in version 1.3 and higher

Compatibility
Framework LeoCorpLibrary LeoCorpLibrary.Core
.NET 5
.NET Core 3.1
.NET Framework 4.7.2
.NET Framework 4.5

The GetPerimeter() allows you to get the perimeter of a circle. Returns a double value.

It's in:

LeoCorpLibrary.Maths.Circle.GetPerimeter()

This method has one argument:

Value Argument Description Example
double radius Circle's radius 14.1

Here's an example of usage:

C#

double circlePerimeter = Maths.Circle.GetPerimeter(11.2);

VB

Dim circlePerimeter As Double = Maths.Circle.GetPerimeter(11.2)

Go to top

# Rectangle

# a. GetDiagonal

This function is available in version 3.2 and higher

Compatibility
Framework LeoCorpLibrary LeoCorpLibrary.Core
.NET 5
.NET Core 3.1
.NET Framework 4.7.2
.NET Framework 4.5

The GetDiagonal() method allows you to get a rectangle's diagonal. It returns a double value.

It's in:

LeoCorpLibrary.Maths.Rectangle.GetDiagonal()

This method has two arguments:

Value Argument Description Example
double width Rectangle's width/base 4.12
double length Rectangle's length 8.5

Here's an example of usage:

C#

double diagonal = Maths.Rectangle.GetDiagonal(4.12, 8.5); // Get diagonal

VB

Dim diagonal As Double = Maths.Rectangle.GetDiagonal(4.12, 8.5) ' Get diagonal

Go to top

# b. GetArea

This function is available in version 3.10 and higher

Compatibility
Framework LeoCorpLibrary LeoCorpLibrary.Core
.NET 5
.NET Core 3.1
.NET Framework 4.7.2
.NET Framework 4.5

The GetArea() method allows you to get a rectangle's area. It returns a double value.

It's in:

LeoCorpLibrary.Maths.Rectangle.GetArea()

This method has two arguments:

Value Argument Description Example
double width Rectangle's width/base 6
double length Rectangle's length 12.2

Here's an example of usage:

C#

double area = Maths.Rectangle.GetArea(5, 10);
// area = 50

VB

Dim area = Maths.Rectangle.GetArea(5, 10)
' area = 50

Go to top

# Triangle

# a. GetArea

This function is available in version 1.3 and higher

Compatibility
Framework LeoCorpLibrary LeoCorpLibrary.Core
.NET 5
.NET Core 3.1
.NET Framework 4.7.2
.NET Framework 4.5

The GetArea() method allows you to get the area of a triangle. Returns a double value.

It's in:

LeoCorpLibrary.Maths.Triangle.GetArea()

This method has two arguments:

Value Argument Description Example
double height Triangle's height 5.48
double width Triangle's width/base 4.12

Here's an example of usage:

C#

double triangleArea = Maths.Triangle.GetArea(5.48, 4.12);

VB

Dim triangleArea As Double = Maths.Triangle.GetArea(5.48, 4.12)

Go to top

# b. GetPerimeter

This function is available in version 1.3 and higher

Compatibility
Framework LeoCorpLibrary LeoCorpLibrary.Core
.NET 5
.NET Core 3.1
.NET Framework 4.7.2
.NET Framework 4.5

The GetPerimeter() method allows you to get the perimeter of a triangle. Returns a double value.

It's in:

LeoCorpLibrary.Maths.Triangle.GetPerimeter()

This method has three arguments:

Value Argument Description Example
double side1 Triangle's side 5.48
double side2 Triangle's side 4.12
double side3 Triangle's side 6

Here's an example of usage:

C#

double trianglePerimeter = Maths.Triangle.GetPerimeter(5.48, 4.12, 6);

VB

Dim trianglePerimeter As Double = Maths.Triangle.GetPerimeter(5.48, 4.12, 6)

Go to top

# c. IsBuildable

This function is available in version 1.3 and higher

Compatibility
Framework LeoCorpLibrary LeoCorpLibrary.Core
.NET 5
.NET Core 3.1
.NET Framework 4.7.2
.NET Framework 4.5

The IsBuildable() method allows you to know if the specified dimensions can build a triangle. Returns a double value.

It's in:

LeoCorpLibrary.Maths.Triangle.IsBuildable()

This method has three arguments:

Value Argument Description Example
double side1 Triangle's side 4.5
double side2 Triangle's side 9.1
double side3 Triangle's side 12.45

Here's an example of usage:

C#

bool isBuildable = Maths.Triangle.IsBuildable(4.5, 9.1, 12.45);

VB

Dim isBuildable As Bool = Maths.Triangle.IsBuildable(4.5, 9.1, 12.45)

Go to top

# d. GetHypotenuse

This function is available in version 3.2 and higher

Compatibility
Framework LeoCorpLibrary LeoCorpLibrary.Core
.NET 5
.NET Core 3.1
.NET Framework 4.7.2
.NET Framework 4.5

The GetHypotenuse() method allows you to get a triangle's hypotenuse from the two other sides. (Pythagorus) It returns a double value.

It's in:

LeoCorpLibrary.Maths.Triangle.GetHypotenuse()

This method has two arguments:

Value Argument Description Example
double side1 Triangle's side 4.5
double side2 Triangle's side 6.1

Here's an example of usage:

C#

double hypotenuse = Maths.Triangle.GetHypotenuse(4.5, 6.1); // Get the hypotenuse

VB

Dim hypotenuse As Double = Maths.Triangle.GetHypotenuse(4.5, 6.1) ' Get the hypotenuse

Go to top

# e. IsRight

This function is available in version 3.10 and higher

Compatibility
Framework LeoCorpLibrary LeoCorpLibrary.Core
.NET 5
.NET Core 3.1
.NET Framework 4.7.2
.NET Framework 4.5

The IsRight() method allows you to get if a triangle is right or not. It returns a bool value.

It's in:

LeoCorpLibrary.Maths.Triangle.IsRight()

This method has two arguments:

Value Argument Description Example
double side1 Triangle's side 4.5
double side2 Triangle's side 6.1
double side3 Triangle's side 8

Here's an example of usage:

C#

bool isRight = Maths.Triangle.IsRight(3, 4, 5);
// isRight = true

VB

Dim isRight As Boolean = Maths.Triangle.IsRight(3, 4, 5)
' isRight = true

Go to top

# Cube

# a. GetVolume

This function is available in version 1.8 and higher

Compatibility
Framework LeoCorpLibrary LeoCorpLibrary.Core
.NET 5
.NET Core 3.1
.NET Framework 4.7.2
.NET Framework 4.5

The GetVolume() method allows you to get the volume of a cube.

It's in:

LeoCorpLibrary.Maths.Cube.GetVolume()

This method has two variation:

Variante 1

GetVolume(double side, double height) {...}

Here's the arguments:

Value Argument Description Example
double side Cube's side 7.1
double height Cube's height 3.8

Variante 2

GetVolume(double side) {...}

Here's the arguments:

Value Argument Description Example
double side Cube's side 8

Here's an example of usage:

C#

// In the case of a rectangular prism
double volume = Maths.Cube.GetVolume(12, 14);

// In the case of a cube
double volumeCube = Maths.Cube.GetVolume(12);

VB

' In the case of a rectangular prism
Dim volume As Double = Maths.Cube.GetVolume(12, 14)

' In the case of a cube
Dim volumeCube As Double = Maths.Cube.GetVolume(12)

Go to top

# b. GetEdge

This function is available in version 1.8.1 and higher

Compatibility
Framework LeoCorpLibrary LeoCorpLibrary.Core
.NET 5
.NET Core 3.1
.NET Framework 4.7.2
.NET Framework 4.5

The GetEdge() method enables you to get the edge of a cube. Returns a double value.

It's in:

LeoCorpLibrary.Maths.Cube.GetEdge()

It has one argument:

Value Argument Description Example
double area Area of the cube 41.5

Here's an example of usage:

C#

double areaBase = Maths.Cube.GetEdge(31);

VB

Dim areaBase As Double = Maths.Cube.GetEdge(31)

Go to top

# Cylinder

# a. GetVolume

This function is available in version 1.8 and higher

Compatibility
Framework LeoCorpLibrary LeoCorpLibrary.Core
.NET 5
.NET Core 3.1
.NET Framework 4.7.2
.NET Framework 4.5

The GetVolume() method enables you to get the volume of a cylinder. Returns a double value.

It's in:

LeoCorpLibrary.Maths.Cylinder.GetVolume()

It has two arguments:

Value Argument Description Example
double radius Cylinder's radius 4.5
double height Cylinder's height 7

Here's an example of usage:

C#

// Get the volume of a cylinder
double volume = Maths.Cylinder.GetVolume(13, 5);

VB

' Get the volume of a cylinder
Dim volume As Double = Maths.Cylinder.GetVolume(13, 5)

Go to top

# b. GetHeight

This function is available in version 1.8.1 and higher

Compatibility
Framework LeoCorpLibrary LeoCorpLibrary.Core
.NET 5
.NET Core 3.1
.NET Framework 4.7.2
.NET Framework 4.5

The GetHeight() method enables you to get the height of a cylinder. Returns a double value.

It's in:

LeoCorpLibrary.Maths.Cylinder.GetHeight()

It has two arguments:

Value Argument Description Example
double radius Cylinder's radius 4.5
double area Cylinder's area 21

Here's an example of usage:

C#

double height = Maths.Cylinder.GetHeight(5, 21);

VB

Dim height As Double = Maths.Cylinder.GetHeight(5, 21)

Go to top

# c. GetBaseArea

This function is available in version 1.8.1 and higher

Compatibility
Framework LeoCorpLibrary LeoCorpLibrary.Core
.NET 5
.NET Core 3.1
.NET Framework 4.7.2
.NET Framework 4.5

The GetBaseArea() method allows you to get the area of the base of a cylinder. Returns a double value.

It's in:

LeoCorpLibrary.Maths.Cylinder.GetBaseArea()

It has two arguments:

Value Argument Description Example
double radius Cylinder's radius 12

Here's an example of usage:

C#

double baseArea = Maths.Cylinder.GetBaseArea(10);

VB

Dim baseArea As Double = Maths.Cylinder.GetBaseArea(10)

Go to top

# Pyramid

# a. GetVolume

This function is available in version 1.8 and higher

Compatibility
Framework LeoCorpLibrary LeoCorpLibrary.Core
.NET 5
.NET Core 3.1
.NET Framework 4.7.2
.NET Framework 4.5

The GetVolume() method allows you to get the volume of a pyramid. Returns a double value.

It's in:

LeoCorpLibrary.Maths.Pyramid.GetVolume()

It has three arguments:

Value Argument Description Example
double length Lenght of the pyramid 4.5
double width Width of the pyramid 7
double height Height of the pyramid 8.9

Here's an example of usage:

C#

// Get the volume of a pyramid
double volume = Maths.Pyramid.GetVolume(13, 5, 15);

VB

' Get the volume of a pyramid
Dim volume As Double = Maths.Pyramid.GetVolume(13, 5, 15)

Go to top

# b. GetHeight

This function is available in version 1.8.1 and higher

Compatibility
Framework LeoCorpLibrary LeoCorpLibrary.Core
.NET 5
.NET Core 3.1
.NET Framework 4.7.2
.NET Framework 4.5

The GetHeight() method allows you to get the height of a pyramid. Returns a double value.

It's in:

LeoCorpLibrary.Maths.Pyramid.GetHeight()

It has three arguments:

Value Argument Description Example
double length Lenght of the pyramid 4.5
double width Width of the pyramid 7
double volume Volume de la pyramide 8.9

Here's an example of usage:

C#

double height = Maths.Pyramid.GetHeight(10, 10, 100).

VB

Dim height As Double = Maths.Pyramid.GetHeight(10, 10, 100)

Go to top

# c. GetLenghtBase

This function is available in version 1.8.1 and higher

Compatibility
Framework LeoCorpLibrary LeoCorpLibrary.Core
.NET 5
.NET Core 3.1
.NET Framework 4.7.2
.NET Framework 4.5

The GetLenghtBase() allows you to get the length of the base of a pyramid. Returns a double value.

It's in:

LeoCorpLibrary.Maths.Pyramid.GetLenghtBase()

It has two arguments:

Value Argument Description Example
double areaBase Base's area 9.9
double width Width 12

Here's an example of usage:

C#

double lengthBase = Maths.Pyramid.GetLenghtBase(100, 10);

VB

Dim lengthBase As Double = Maths.Pyramid.GetLenghtBase(100, 10)

Go to top

# d. GetWidthBase

This function is available in version 1.8.1 and higher

Compatibility
Framework LeoCorpLibrary LeoCorpLibrary.Core
.NET 5
.NET Core 3.1
.NET Framework 4.7.2
.NET Framework 4.5

The GetWidthBase() allows you to get the width of the base of a pyramid. Returns a double value.

It's in:

LeoCorpLibrary.Maths.Pyramid.GetWidthBase()

It has two arguments:

Value Argument Description Example
double areaBase Base's area 6.1
double length Lenght 15

Here's an example of usage:

C#

double widthBase = Maths.Pyramid.GetWidthBase(100, 10);

VB

Dim widthBase As Double = Maths.Pyramid.GetWidthBase(100, 10)

Go to top

# Hexagon

# a. GetArea

This function is available in version 3.2 and higher

Compatibility
Framework LeoCorpLibrary LeoCorpLibrary.Core
.NET 5
.NET Core 3.1
.NET Framework 4.7.2
.NET Framework 4.5

The GetArea() method allows you to get the area of an hexagon from the length of it's side. It returns a double value.

It's in:

LeoCorpLibrary.Maths.Hexagon.GetArea()

It has one argument:

Value Argument Description Example
double side Lenght of the hexagon's side 8

Here's an example of usage:

C#

double hexagonArea = Maths.Hexagon.GetArea(8); // Get the area

VB

Dim hexagonArea As Double = Maths.Hexagon.GetArea(8) ' Get the area

Go to top

# b. GetPerimeter

This function is available in version 3.2 and higher

Compatibility
Framework LeoCorpLibrary LeoCorpLibrary.Core
.NET 5
.NET Core 3.1
.NET Framework 4.7.2
.NET Framework 4.5

The GetPerimeter() method allows you to get the perimeter of a hexagon. It returns a double value.

It's in:

LeoCorpLibrary.Maths.Hexagon.GetPerimeter()

It has one argument:

Value Argument Description Example
double side Lenght of the hexagon's side 7.2

Here's an example of usage:

C#

double hexagonPerimeter = Maths.Hexagon.GetPerimeter(7.2); // Get perimeter

VB

Dim hexagonPerimeter As Double = Maths.Hexagon.GetPerimeter(7.2) ' Get perimeter

Go to top

# Diamond

# a. GetArea

This function is available in version 3.2 and higher

Compatibility
Framework LeoCorpLibrary LeoCorpLibrary.Core
.NET 5
.NET Core 3.1
.NET Framework 4.7.2
.NET Framework 4.5

The GetArea() method allows you to get the area of a diamond. It returns a double value.

It's in:

LeoCorpLibrary.Maths.Diamond.GetArea()

It has one argument:

Value Argument Description Example
double diag1 Lenght of the diamond's diagonal 4.5
double diag2 Lenght of the diamond's diagonal 7.5

Here's an example of usage:

C#

double diamondArea = Maths.Diamond.GetArea(4.5, 7.5); // Get area

VB

Dim diamondArea As Double = Maths.Diamond.GetArea(4.5, 7.5) ' Get area

Go to top

# b. GetPerimeter

This function is available in version 3.2 and higher

Compatibility
Framework LeoCorpLibrary LeoCorpLibrary.Core
.NET 5
.NET Core 3.1
.NET Framework 4.7.2
.NET Framework 4.5

The GetPerimeter() method allows you to get the area of a diamond. It returns a double value.

It's in:

LeoCorpLibrary.Maths.Diamond.GetPerimeter()

It has one argument:

Value Argument Description Example
double side Lenght of the diamond's side 8

Here's an example of usage:

C#

double diamondPerimeter = Maths.Diamond.GetPerimeter(8); // Get perimeter

VB

Dim diamondPerimeter As Double = Maths.Diamond.GetPerimeter(8) ' Get perimeter

Go to top

# Sphere

# a. GetArea

This function is available in version 3.8 and higher

Compatibility
Framework LeoCorpLibrary LeoCorpLibrary.Core
.NET 5
.NET Core 3.1
.NET Framework 4.7.2
.NET Framework 4.5

The GetArea() method allows you to get the area of a sphere from its radius. It returns a double value.

It's in:

LeoCorpLibrary.Maths.Sphere.GetArea()

It has one argument:

Value Argument Description Example
double radius Radius of the sphere 10

Here's an example of usage:

C#

double area = Maths.Sphere.GetArea(10);
// Expected output:
// 1256.6370614359173

VB

Dim area As Double = Maths.Sphere.GetArea(10)
' Expected output:
' 1256.6370614359173

Go to top

# b. GetVolume

This function is available in version 3.8 and higher

Compatibility
Framework LeoCorpLibrary LeoCorpLibrary.Core
.NET 5
.NET Core 3.1
.NET Framework 4.7.2
.NET Framework 4.5

The GetVolume() method allows you to get the volume of a sphere from its radius. It returns a double value.

It's in:

LeoCorpLibrary.Maths.Sphere.GetVolume()

It has one argument:

Value Argument Description Example
double radius Radius of the sphere 10

Here's an example of usage:

C#

double volume = Maths.Sphere.GetVolume(10);
// Expected output:
// 4188.790204786391

VB

Dim volume As Double = Maths.Sphere.GetVolume(10)
' Expected output:
' 4188.790204786391

Go to top

# Cone

# a. GetVolume

This function is available in version 3.10 and higher

Compatibility
Framework LeoCorpLibrary LeoCorpLibrary.Core
.NET 5
.NET Core 3.1
.NET Framework 4.7.2
.NET Framework 4.5

The GetVolume() method allows you to get the volume of a cone. It returns a double value.

It's in:

LeoCorpLibrary.Maths.Cone.GetVolume()

This method has two arguments:

Value Argument Description Example
double radius The radius of the cone 10.4
double height The height of the cone 9.5

Here's an example of usage:

C#

double volume = Maths.Cone.GetVolume(5, 20);
// volume = 523.5987755982989

VB

Dim volume As Double = Maths.Cone.GetVolume(5, 20)
' volume = 523.5987755982989

Go to top

# Trigonometry functions

SohCahToa

# a. GetTriangleOpposedSideFromHypotenuse

This function is available in version 3.5 and higher

Compatibility
Framework LeoCorpLibrary LeoCorpLibrary.Core
.NET 5
.NET Core 3.1
.NET Framework 4.7.2
.NET Framework 4.5

The GetTriangleOpposedSideFromHypotenuse() allows you to get a triangle's opposed side from an angle, and its hypotenuse. Returns a double value.

It's in:

LeoCorpLibrary.Maths.Trigonometry.GetTriangleOpposedSideFromHypotenuse()

It has one argument:

Value Argument Description Example
double angle The angle value (in radians) 1.2
double hypotenuse The hypotenuse length value 12

Here's an example of usage:

Image

C#

double opposedSide = Maths.Trigonometry.GetTriangleOpposedSideFromHypotenuse(1.05, 10);
// Expected result: 8.66
// Actual result: 8.67423225594017

VB

Dim opposedSide As Double = Maths.Trigonometry.GetTriangleOpposedSideFromHypotenuse(1.05, 10)
' Expected result: 8.66
' Actual result: 8.67423225594017

Go to top

# b. GetTriangleOpposedSideFromAdjacent

This function is available in version 3.5 and higher

Compatibility
Framework LeoCorpLibrary LeoCorpLibrary.Core
.NET 5
.NET Core 3.1
.NET Framework 4.7.2
.NET Framework 4.5

The GetTriangleOpposedSideFromAdjacent() method allows you to get a triangle's opposed side from an angle, and its adjacent side. It returns a double value.

It's in:

LeoCorpLibrary.Maths.Trigonometry.GetTriangleOpposedSideFromAdjacent()

It has one argument:

Value Argument Description Example
double angle The angle value (in radians) 1.02
double adjacent The adjacent side length value 5

Here's an example of usage:

Image

C#

double opposedSide = Maths.Trigonometry.GetTriangleOpposedSideFromAdjacent(1.05, 5);
// Expected result: 8.66
// Actual result: 8.716576549915851

VB

Dim opposedSide As Double = Maths.Trigonometry.GetTriangleOpposedSideFromAdjacent(1.05, 5)
' Expected result: 8.66
' Actual result: 8.716576549915851

Go to top

# c. GetTriangleAdjacentSideFromHypotenuse

This function is available in version 3.5 and higher

Compatibility
Framework LeoCorpLibrary LeoCorpLibrary.Core
.NET 5
.NET Core 3.1
.NET Framework 4.7.2
.NET Framework 4.5

The GetTriangleAdjacentSideFromHypotenuse() method allows you to get a triangle's adjacent side from an angle, and its hypotenuse. Returns a double value.

It's in:

LeoCorpLibrary.Maths.Trigonometry.GetTriangleAdjacentSideFromHypotenuse()

It has one argument:

Value Argument Description Example
double angle The angle value (in radians) 1.02
double hypotenuse The hypotenuse side length value 5

Here's an example of usage:

Image

C#

double adjacentSide = Maths.Trigonometry.GetTriangleAdjacentSideFromHypotenuse(1.05, 10);
// Expected result: 5
// Actual result: 4.97571047891727

VB

Dim opposedSide As Double = Maths.Trigonometry.GetTriangleAdjacentSideFromHypotenuse(1.05, 10)
' Expected result: 5
' Actual result: 4.97571047891727

Go to top

# d. GetTriangleAdjacentSideFromOpposedSide

This function is available in version 3.5 and higher

Compatibility
Framework LeoCorpLibrary LeoCorpLibrary.Core
.NET 5
.NET Core 3.1
.NET Framework 4.7.2
.NET Framework 4.5

The GetTriangleAdjacentSideFromOpposedSide() method allows you to get a triangle's adjacent side from an angle, and its opposed side. Returns a double value.

It's in:

LeoCorpLibrary.Maths.Trigonometry.GetTriangleAdjacentSideFromOpposedSide()

It has one argument:

Value Argument Description Example
double angle The angle value (in radians) 1.2
double opposed The opposed side length value 8.6

Here's an example of usage:

Image

C#

double adjacentSide = Maths.Trigonometry.GetTriangleAdjacentSideFromOpposedSide(1.05, 8.66);
// Expected result: 5
// Actual result: 4.967546576576329

VB

Dim adjacentSide As Double = Maths.Trigonometry.GetTriangleAdjacentSideFromOpposedSide(1.05, 8.66)
' Expected result: 5
' Actual result: 4.967546576576329

Go to top

# e. GetTriangleHypotenuseFromOpposedSide

This function is available in version 3.5 and higher

Compatibility
Framework LeoCorpLibrary LeoCorpLibrary.Core
.NET 5
.NET Core 3.1
.NET Framework 4.7.2
.NET Framework 4.5

The GetTriangleHypotenuseFromOpposedSide() method allows you to get a triangle's hypotenuse from an angle, and its opposed side. Returns a double value.

It's in:

LeoCorpLibrary.Maths.Trigonometry.GetTriangleHypotenuseFromOpposedSide()

It has one argument:

Value Argument Description Example
double angle The angle value (in radians) 1.2
double opposed The opposed side length value 8.6

Here's an example of usage:

Image

C#

double hypotenuse = Maths.Trigonometry.GetTriangleHypotenuseFromOpposedSide(1.05, 8.66);
// Expected result: 10
// Actual result: 9.98359248920223

VB

Dim hypotenuse As Double = Maths.Trigonometry.GetTriangleHypotenuseFromOpposedSide(1.05, 8.66)
' Expected result: 10
' Actual result: 9.98359248920223

Go to top

# f. GetTriangleHypotenuseFromAdjacentSide

This function is available in version 3.5 and higher

Compatibility
Framework LeoCorpLibrary LeoCorpLibrary.Core
.NET 5
.NET Core 3.1
.NET Framework 4.7.2
.NET Framework 4.5

The GetTriangleHypotenuseFromAdjacentSide() method allows you to get a triangle's hypotenuse from an angle, and its adjacent side. Returns a double value.

It's in:

LeoCorpLibrary.Maths.Trigonometry.GetTriangleHypotenuseFromAdjacentSide()

It has one argument:

Value Argument Description Example
double angle The angle value (in radians) 1.2
double adjacent The adjacent side length value 8.6

Here's an example of usage:

Image

C#

double hypotenuse = Maths.Trigonometry.GetTriangleHypotenuseFromAdjacentSide(1.05, 5);
// Expected result: 10
// Actual result: 10.04881618652381

VB

Dim hypotenuse As Double = Maths.Trigonometry.GetTriangleHypotenuseFromAdjacentSide(1.05, 5)
' Expected result: 10
' Actual result: 10.04881618652381

Go to top